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Valinto
Mathematics
15 May, 07:45
2y-3[3-4 (y-5) + 2 (1-3y) ]
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Zariah Baxter
15 May, 07:51
0
- 75 - 32y
Step-by-step explanation:
2y-3[3-4 (y-5) + 2 (1-3y) ]
= 2y - 3 (3 - 4y + 20 + 2 - 6y)
= 2y - 3 (25 - 10y)
= 2y - 75 - 30y
= - 75 - 32y
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Twinkly
15 May, 08:02
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Step-by-step explanation:
2y-3[3-4 (y-5) + 2 (1-3y) ] = 2y - 3[ 3 - 4*y - (-4) * 5 + 2*1 - 2*3y]
= 2y - 3[ 3 - 4y + 20 + 2 - 6y]
= 2y - 3[ 3+20+2 - 4y-6y] {bring the like terms together}
=2y - 3 [25 - 10y]
=2y - 3*25 - (-3) * 10y
= 2y - 75 + 30y
= 32y - 75
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