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13 March, 21:19

The length of a rectangle is 5 feet more than twice the width. The perimeter is 130 feet. Find the dimensions.

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  1. 13 March, 21:25
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    So,

    The problem tells us that the length of the rectangle is 5 feet more than twice the width.

    Mathematically:

    length = 5 + 2width

    l = 5 + 2w

    We know that the perimeter is 2l + 2w.

    2l + 2w = 130

    2 (5 + 2w) + 2w = 130

    Distribute

    10 + 4w + 2w = 130

    Collect Like Terms

    10 + 6w = 130

    Subtract 10 from both sides

    6w = 120

    Divide both sides by 6

    w = 20

    The width is 20.

    Since

    l = 5 + 2w

    Substitute

    l = 5 + 2 (20)

    Multiply

    l = 5 + 40

    Collect Like Terms

    l = 45

    The length is 45.

    Check

    2l + 2w = 130

    2 (45) + 2 (20) = 130

    90 + 40 = 130

    130 = 130

    Width: 20 ft.

    Length: 45 ft.
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