At what temperature will 0.0100 mole of argon gas have a volume of 275 ml at 100.0 kpa?

Question

Braiden Shea

Mathematics

29 May, 10:04

At what temperature will 0.0100 mole of argon gas have a volume of 275 ml at 100.0 kpa?

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Answers (1)

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Kristen Mclaughlin · Answer 1

The main formula is

PxV = nx RxT

P: pressure=100.0 Kpa, and 1 atm = 101.325 kilopascal (kPa), so 100Kpa=0.9atm

V : volume=0.275l

n: number of moles = 0.0100mole

R: Gas constant=8.31

T: temperature

so T = PxV / nx R=0.9 x0.275 / 0.01 x8.31=2.97°, so T=2.97°+273=275.97K