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28 December, 07:37

Solve the following system of equations by substitution and select the correct answer below:

6x - 4y = 36

2x - 8y = 32

x = 4, y = 3

x = 4, y = - 3

x = - 4, y = 3

x = - 4, y = - 3

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Answers (2)
  1. 28 December, 07:57
    0
    The answer is x = 4 and y = - 3

    6x-4y=36 - - (1)

    2x-8y=32 - (2)

    from (1)

    -4y = 36-6x

    y = - 9+3/2x

    (3) into (2)

    2x-8 (-9+3/2x) = 32

    2x+72-12x=32

    72-10x=32

    -10x = - 40

    x = 4

    sub x=4 into y = - 9+3/2x

    y = - 9+3/2 (4)

    y = - 3
  2. 28 December, 08:00
    0
    First, we take one of our equations and solve for one variable in terms of the other.

    This is similar to solving a one-variable equation.

    6x - 4y = 36

    Get one variable on one side.

    6x = 36 + 4y

    Divide by 6.

    x = 6 + 2/3y

    Now, we substitute this value for x in our second equation.

    2x - 8y = 32

    2 (6 + 2/3y) - 8y = 32

    Distribute the 2 ...

    12 + 4/3y - 8y = 32

    Subtract 12 from each side ...

    4/3y - 8y = 20

    Multiply everything by 3 to get rid of that fraction.

    4y - 24y = 60

    -20y = 60

    Divide by - 20 ...

    y = - 3

    Use this value in an earlier equation to find x.

    6x - 4y = 36

    6x - 4 (-3) = 36

    6x + 12 = 36

    6x = 24

    x = 4
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