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7 December, 14:14

Find the equation of a circle which is tangent to x-axis and whose center is at (4,2)

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  1. 7 December, 14:43
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    Hello:

    an equation x-axis is y = 0

    the ridus is the distance betwen the center and x-axis:

    r = | (0) (4) + (1) (2) + 0 | / √ ((0) ² + (1) ²) = 2/1 = 2

    an equation of the circle is : (x - 4) ² + (y-2) ² = 4
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