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3 April, 07:25

A standard number cube is tossed. Find P (3 or odd)

A. 1/2

B. 2/3

C. 1/3

D. 1/6

+3
Answers (2)
  1. 3 April, 07:36
    0
    E = event space = set of outcomes we want to happen

    E = set of numbers that are either 3 or odd

    E = {1, 3, 5}

    S = sample space = set of all possible outcomes

    S = set of all the values on the standard number cube (aka dice)

    S = {1, 2, 3, 4, 5, 6}

    There are 3 items in the event space out of 6 total in the sample space

    Using math notation, we can say n (E) = 3 and n (S) = 6. The small n means "number". So writing "n (E) " means "number of items in the event space".

    So,

    P (3 or odd) = n (E) / n (S)

    P (3 or odd) = 3/6

    P (3 or odd) = 1/2

    The probability as a fraction is 1/2, which is 0.5 in decimal form. This represents a chance of 50%. Note: since 3 is an odd number, saying "P (3 or odd) " is the same as just saying "P (odd) "

    Answer: Choice A. 1/2
  2. 3 April, 07:44
    0
    Total number of possible outcomes = 6

    Total number of outcomes with 3 or odd = 3

    They are : 1, 3, 5

    P (3 or odd) = 3/6 = 1/2

    Answer: 1/2
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