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Samir Macias
Mathematics
17 May, 12:20
How do you solve this?
5 = log3 (x^2 + 18)
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Camryn Stevenson
17 May, 12:48
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Since x is on the right side of the equation, switch the sides so it is on the left side of the equation. log3 (x2 + 18) = 5 log3 x2 + 18 = 5
Rewrite log3 (x2 + 18) = 5 log3 x2 + 18 = 5 in exponential form using the definition of a logarithm. If x and b are positive real numbers and b≠1, then logb (x) = y is equivalent to b^y = x. 3^5 = x^2 + 18
Raise 3 to the power of 5 to get 243. 243 = x^2 + 18 Since x is on the right side of the equation, switch the sides so it is on the left side of the equation. x^2 + 18 = 35 Raise 3 to the power of 5 to get 243. x^2 + 18 = 243 Move all terms not containing x to the right side of the equation
Since 18 does not contain the variable to solve for, move it to the right side of the equation by subtracting 18 from both sides. x^2 = - 18 + 243 Add - 18 and 243to get 225. x^2 = 225
' Take the square root of both sides of the equation to eliminate the exponent on the left side. x = ± √225 x The complete solution is the result of both the positive and negative portions of the solution.
Rewrite 225 as 152. x = ± √ 152 Pull terms out from under the radical, assuming positive real numbers. x = ± 15
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