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Mara Skinner
Mathematics
18 February, 17:52
Solve: 2x^2-28x+106=0
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Rachel Hood
18 February, 18:17
0
Use the quadratic formula to find the solutions.
-b±√b2-4 (ac) 2a-b±b2-4 (ac) 2a
subtite the values
a=2a=2,
b=-28b=-28, and
c=98c=98 into the quadratic formula and solve for
xx. 28±√ (-28) 2-4⋅ (2⋅98) 2⋅228± (-28) 2-4⋅ (2⋅98) 2⋅2Simplify.
Simplify the numerator.
x=28±02⋅2x=28±02⋅4 Multiply
22 by 22. x=28±04x=28±04 Simplify
28±0428±04. x=284x=284Divide 2828 by 44. x=7x=7
The final answer is the combination of both solutions.
x=7x=7 Double roots
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