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18 February, 17:52

Solve: 2x^2-28x+106=0

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  1. 18 February, 18:17
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    Use the quadratic formula to find the solutions.

    -b±√b2-4 (ac) 2a-b±b2-4 (ac) 2a

    subtite the values

    a=2a=2,

    b=-28b=-28, and

    c=98c=98 into the quadratic formula and solve for

    xx. 28±√ (-28) 2-4⋅ (2⋅98) 2⋅228± (-28) 2-4⋅ (2⋅98) 2⋅2Simplify.

    Simplify the numerator.

    x=28±02⋅2x=28±02⋅4 Multiply

    22 by 22. x=28±04x=28±04 Simplify

    28±0428±04. x=284x=284Divide 2828 by 44. x=7x=7

    The final answer is the combination of both solutions.

    x=7x=7 Double roots
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