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23 July, 03:39

If the largest angle of a triangle is 120 degrees and it is included between sides of 1.5 and 0.5, what is the largest side of the triangle to the nearest tenth?

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  1. 23 July, 03:44
    0
    C²=a²+b²-2·a·b·cos (C)

    c² = (1.5) ² + (0.5) - 2 · (l·5) · (0.5) ·cos (120°)

    c² = 3.25

    c = √3.25

    c=1.802775638

    To nearest tenth, c=1.8
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