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21 November, 22:27

A force of 50 pounds is exerted at an angle of 80 with the horizontal. What is its horizontal component?

a. 9 lb.

b. 29 lb.

c. 49 lb.

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Answers (1)
  1. 21 November, 22:42
    0
    Option A is the correct answer.

    Explanation:

    Any vector can be resolved in to two components. Horizontal component and vertical component.

    Consider a vector F which is at angle θ⁰ to the horizontal, we can resolve this vector in to two.

    Horizontal component = F cos θ

    Vertical component = F sin θ

    Here we have Force, F = 50 pounds

    Angle with horizontal = 80°

    Horizontal component = F cos θ = 50 * cos 80 = 8.68 pounds

    ≅ 9 lb.

    Option A is the correct answer.
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