A juggler has a bag containing three yellow balls, six green balls, three blue balls, and one red ball, all the same size. The juggler pulls a ball from the bag at random. Then, without replacing it, he pulls out a second ball. What is the probability that the juggler first draws a green ball followed by a blue ball?

Lets put in the mind first we are finding a probability for without replacement.

Here we have 6 green, 3 blue, 1red balls

Probability of picking a green ball=Total Green/Total

which is going to be P1 = 6/6+3+1=6/10=0.6

Now we are not putting back green ball in the bag again

Probability of Blue ball=Total blue balls/Total (new)

P2 = 3/9=0.33

Now total will become 1 less than before as we did not put green ball back in the bag.

Now add them up = p1+p2=0.6+0.33=0.27