Two three-digit numbers are made up of six different digits. The first digit of the second number is twice as big as the last digit of the first number. (Note: 0 is also a digit but cannot be the first digit of a number!)

How big is the smallest possible sum of the two numbers?

Question

Rene Booth

Mathematics

25 May, 08:49

Two three-digit numbers are made up of six different digits. The first digit of the second number is twice as big as the last digit of the first number. (Note: 0 is also a digit but cannot be the first digit of a number!)

How big is the smallest possible sum of the two numbers?

+2

Answers (1)

Know the Answer?

Nathalie Ritter · Answer 1

Answer:the smallest possible sum of the two numbers is 537

Step-by-step explanation:

Two three-digit numbers are made up of six different digits.

To interpret this, let the two three digit numbers be;

ABC and. DEF

The first digit of the second number is twice as big as the last digit of the first number.

Interpret;

D=2C

The first digit of the first number can be 1, the second digit 0 and the third digit 2.

102.

For the second number:

D=2C

The first digit is 4, second digit 3 and last digit 5 since no repetition of digits

435.

Answer:the smallest possible sum of the two numbers is

102+435 = 537

Two three-digit numbers are made up of six different digits. The first digit of the second number is twice as big as the last digit of the first number. (Note: 0 is also a digit but cannot be the first digit of a number!)How big is the smallest possible sum of the two numbers?

Two three-digit numbers are made up of six different digits. The first digit of the second number is twice as big as the last digit of the first number. (Note: 0 is also a digit but cannot be the first digit of a number!)

How big is the smallest possible sum of the two numbers?