If a rectangle has a width of

(4x+3) and a length of (x + 1)

what is the area of the

rectangle?

The rectangle doesn't exists

Step-by-step explanation:

(4x+3). (x+1) = ?

4x² + 4x + 3x + 3 = ?

4x² + 7x + 3 = ?

4 = a

7 = b

3 = c

delta = b² - 4. a. c

delta = 7² - 4.4.3

delta = 49 - 4.4.3

delta = 49 - 48

delta = 1

x1 = - b + (square root) delta / 2. a

x1 = - 7 + 1/2.4

x1 = - 6 / 8

x2 = - 7 - 1/2.4

x2 = - 8/8

x2 = - 1