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Carissa
Mathematics
7 February, 01:08
Factor completely 2c^5 + 44c^4 + 242c^3
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Harvey
7 February, 01:27
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2c^5 + 44c^4 + 242c^3
Take 2 c^3 common:
2 c^3 (c^2 + 22 c + 121)
Factorize the quadratic part:
2 c^3 (c^2 + 22 c + 121)
2 c^3 (c+11) (c+11)
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