X+y-6 = 0

x-y = 0

What is the solution of the system?

(3.3)

(-3.3)

(3,-3)

x = + 3, y = + 3

Step-by-step explanation:

Just solve for x in eq1

to become: x=6-y

then substitute it in eq2

6-y-y=0

6-2y=0

2y=6

y=+3

And finally substitute the value of y in any eqs to find the value of x.

I hope that it's a clear explanation.