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4 June, 14:34

The height of a ball dropped from the top of a 450-foot tall building can be described by the expression

450 - 16r, where

I represents the time, in seconds, after the ball is dropped.

What is the height of the object

4 seconds after it is dropped?

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Answers (1)
  1. 4 June, 15:02
    0
    The answer is 386 feet.

    Step-by-step explanation:

    This equation simply asks to plug in a value that gives you the final value of the height. 450 is the initial height, and r (or l) is referred to as the amount of seconds after the item is dropped. 16 is the constant value of feet that the ball drops within one second.

    Therefore, by substituting 4 for r (or l) and multiplying it by 16, you will receive 64 feet in 4 seconds. Finally, you need to subtract this from 450 feet, giving you a final answer of 386 feet.
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