Janice is 4 inches shorter than David, and David is 2 inches shorter than Evan. If Evan is 13 inches taller than Kathleen and Kathleen is 6 inches shorter than Krysta, by how many inches is Janice taller than Krysta?

Answer: Janice is 1 inch taller than Krysta.

Step-by-step explanation:

Let the height of Krysta denoted by h.

According to the given statements, we will write height of each person in terms of 'h'.

Kathleen is 6 inches shorter than Krysta.

i. e. Height of Kathleen = h-6

Evan is 13 inches taller than Kathleen.

i. e. Height of Evan = (h-6) + 13=h-6+13=h+7

i. e. Height of Evan = h+7

David is 2 inches shorter than Evan.

i. e. Height of David = (h+7) - 2 = h+7-2

Height of David = h+5

Janice is 4 inches shorter than David.

i. e. Height of Janice = (h+5) - 4=h+1

i. e. height of Janice = height of Krysta + 1 inch [∵ h = height of Krysta]

⇒ Janice is 1 inch taller than Krysta.