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29 November, 23:06

How to solve 8x^3-27=0

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Answers (2)
  1. 29 November, 23:16
    0
    8x³-27=0

    8x³=27

    x³=27/8

    x=∛27/∛8

    x=3/2
  2. 29 November, 23:22
    0
    Factor using difference of cubes, and set each factor equal to 0.

    x = (-3+3i/sqrt (3)) / (4), (-3-3i/sqrt (3)) / (4), (3) / (2)
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