An office is Charlie and the speed of 10 1/5 miles per hour how long will it take to object to travel 1 4/5 miles

(10 1/5) / 1 = (1 4/5) / x ... 10 1/5 miles to 1 hr = 1 4/5 miles to x hrs

cross multiply ...

(10 1/5) (x) = (1 4/5) (1)

51/5x = 9/5

x = (9/5) / (51/5)

x = 9/5 * 5/51

x = 9/51 which reduces to 3/17 hrs <==