Suppose that the inside bottom of a box is painted with three colors: 1/3 of the bottom area is red, 1/6 is blue, and 1/2 is white. You toss a tiny pebble into the box without aiming and note the color on which the pebble lands. Then you toss another tiny pebble into the box without aiming and note the color on which that pebble lands. What is the probability that one of the pebbles lands on the color blue and the other pebble lands on red?

Question

Marin Ryan

Mathematics

30 November, 09:50

Suppose that the inside bottom of a box is painted with three colors: 1/3 of the bottom area is red, 1/6 is blue, and 1/2 is white. You toss a tiny pebble into the box without aiming and note the color on which the pebble lands. Then you toss another tiny pebble into the box without aiming and note the color on which that pebble lands. What is the probability that one of the pebbles lands on the color blue and the other pebble lands on red?

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Answers (1)

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Roland Butler · Answer 1

1/18 (5.5%)

Step-by-step explanation:

You have a 1/3 chance to get red the first time and a 1/6 to get blue the second. So to find the compound probability of this you multiply 1/3*1/6.