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Adrian Weber
Mathematics
26 December, 17:55
Solutions to 3|x-1|≥12
+5
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Karlie Bush
26 December, 18:22
0
I dont know if you need a graph but x≥5 or x≥-3
Step-by-step explanation:
solve
3lx-1l≥12
lx-1l≥4
open into two statements x-1≥4 and x-1≥-4
x≥5
x≥-3
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