An athletic field is a 46 yd -by-92 yd rectangle, with a semicircle at each of the short sides. A running track 20 yd wide surrounds the field. If the track is divided into eight lanes of equal width, with lane 1 being the inner-most and lane 8 being the outer-most lane, what is the distance around the track along the inside edge of each lane? A rectangle of length 92 yards and width 46 yards surrounded by a running track of width 20 yards. 92 yd 46 yd 20 yd The length of the track along the inside edge of lane 1 is approximately nothing yd.

Question

Jamal Walter

Mathematics

28 November, 22:25

An athletic field is a 46 yd -by-92 yd rectangle, with a semicircle at each of the short sides. A running track 20 yd wide surrounds the field. If the track is divided into eight lanes of equal width, with lane 1 being the inner-most and lane 8 being the outer-most lane, what is the distance around the track along the inside edge of each lane? A rectangle of length 92 yards and width 46 yards surrounded by a running track of width 20 yards. 92 yd 46 yd 20 yd The length of the track along the inside edge of lane 1 is approximately nothing yd.

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Answers (1)

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Ean Harding · Answer 1

Refer below for detailed explanation.

Step-by-step explanation:

As per the track is divided into 8 lanes. So we will have 8 answers for the distances around the track along the inside edge of each lane.

So,

D=2 (92) + 2 * 1/2 pi*d

Or

D=184+pi*d

Now we start from the innermost edge with the diameter of 46 yd. And we have 8 lanes 20 yd wide so it becomes,

20/8=2.5 so the diameter increases by,

So 2 (2.5) = 5 yd each lane going outward. So 8 distances are,

D1=184+pi*46=328.51

D2=184+pi * (46+5) = 344.221

D3=184+pi * (46+10) = 359.929

D4=184+pi * (46+15) = 375.63

D5=184+pi * (46+20) = 391.345

D6=184+pi * (46+25) = 407.05

D7=184+pi * (46+30) = 422.761

D8=184+pi * (46+35) = 438.469