Three consecutive even integers have a sum of 24. Find the integers

Even integers have the form 2k so three consecutive even integers will be 2k, 2 (k+1),2 (k+2)

so there sum will be

2k+2 (k+1) + 2 (k+2) = 24

simplifying

2k+2k+2+2k+4=24

adding like terms

6k+6=24

6k=18

k=3

so the three consecutive even integers are

2 (3),2 (3+1),2 (3+2)

6,8,10