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12 April, 20:40

R (x) = - x² + 3x s (x) = 2x + 1

(s - r) (x) =

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Answers (2)
  1. 12 April, 20:54
    0
    r (x) = - x² + 3x

    s (x) = 2x + 1

    (s - r) (x) is simply the difference of these functions. Subtract r (x) from s (x):

    (s - r) (x) = s (x) - r (x)

    (s - r) (x) = 2x + 1 - (-x² + 3x)

    (s - r) (x) = 2x + 1 + x² - 3x

    (s - r) (x) = x² - x + 1
  2. 12 April, 21:05
    0
    (s-r) (x) = x²-x+1

    Step-by-step explanation:

    We have given two functions.

    r (x) = - x²+3x and s (x) = 2x+1

    We have to find the difference of two functions.

    (s-r) (x) = ?

    The formula to find the difference of two functions is:

    (s-r) (x) = s (x) - r (x)

    Putting the value of given functions in above formula, we have

    (s-r) (x) = (2x+1) - (-x²+3x)

    (s-r) (x) = 2x+1+x²-3x

    (s-r) (x) = x² + (-3+2) x+1

    (s-r) (x) = x² + (-1) x+1

    (s-r) (x) = x²-x+1 which is the answer.
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