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Baylee Colon
Mathematics
4 May, 15:41
If f (x) = 4x-8, what is f^-1 (x)
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Nathan Herrera
4 May, 15:45
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X = 4x - 8
let's replace x with y.
y = 4x - 8
y + 8 = 4x
x = y/4 + 8/4
x = y/4 + 2
and now replace y with x.
so x = x/4 + 2
and inverse f^-1
f^-1 (x) = x/4 + 2
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