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21 April, 13:47

A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function = ht-64t16t2. What is the maximum height that the ball will reach?

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  1. 21 April, 13:55
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    This is the concept of applications of polynomial equations. Given that the height of the ball is modeled by the function:

    h (t) = 16t^2-64t

    the maximum height will be calculated as follows;

    h (t) = 16t (t-4)

    therefore:

    t=0 or t=4

    h (4) = - 64 (4) + 16 (4^2)

    =0
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