Check all that apply. If csc theta = 13/12 then:

a. tan theta = 12/5

b. sin theta = 12/13

c. cos theta = 12/13

d. sec theta = 12/13

Cosec t (heta) = 13/12

1/sin t = 13/12

sin t = 12/13

cos t = √ (1 - (12/13) ²) = √ (1 - 144/169) = √25/169

cos t = 5/13

tan t = sin t / cos t = (12/13) / (5/13) = 12/5

sec t = 1 / cos t = 13/5

Answer: A) and B) are correct:

tan theta = 12/5 and sin theta = 12/13