There are values of t so sin t =.3 and cos t=-.6

Question

Lara Good

Mathematics

28 April, 22:55

There are values of t so sin t =.3 and cos t=-.6

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Answers (2)

Know the Answer?

Zaire Kaufman · Answer 1

What's the question in this I don't understand

Zaniyah Montgomery · Answer 2

A pretty straight way to determine this is to evaluate t for both of these equations, although it may not be the method you are looking for.

For sin (t) =.3

arcsin (.3) = t (that is what the arcsin is)

In degrees that is 17.457603124.

Thus sin (17.457603124) =.3

For cos (t) = -.6

arccos (-.6) = 126.86989765

Now there are multiple values of t where cos (t) = -.6. The values repeat every 360 degrees so, the cos of - 233.13010235 degrees or 486.86989765 degrees also produce -.6. But none of these match the t given by the first equation. So no, there is no value of t that produces sin (t) =.3 AND cos (t) = -.6.