The sum of four consecutive odd integerd is - 72.

n, n + 2, n + 4, n + 6 - four consecutive odd integers

-72 - the sum

The equation:

n + (n + 2) + (n + 4) + (n + 6) = - 72

n + n + 2 + n + 4 + n + 6 = - 72

4n + 12 = - 72 |subtract 12 from both sides

4n = - 84 |divide both sides by 4

n = - 21

n + 2 = - 21 + 2 = - 19

n + 4 = - 21 + 4 = - 17

n + 6 = - 21 + 6 = - 15

Answer: - 21, - 19, - 17, - 15.