When a number is increased by 25% and 11 is added, the result is 51

when a number is increased by 25% and 11 is added, the result is 51:

For a number of (x) we add the increased value of 25%. To this we add 11 to the whole was equal to 51:

x + 25%x + 11 = 51

x + 0,25x = 51 - 11

1,25x = 40 |:1,25

x = 32

The number is 32!

OK, I got it. Now, what is your question?

Do you want to know what the original number is?

Here's how to find it:

First, in order to work with the number, you have to give it a name.

Let's call it 'tom'.

When you increase 'tom' by 25%, you then have (1.25 tom).

Then, when you add 11, you have (1.25tom + 11).

1.25tom + 11 = 51

Subtract 11 from each side of the equation:

1.25tom = 40

Divide each side by 1.25:

tom = 40/1.25 = 32

tom = 32.

A lot of people are bothered by this. They think that every unknown

and every variable in algebra must be named with a letter, like 'x', 'y',

'Q', 'z', or Θ (that's 'theta'). But there's no reason for that, only custom.

We can give any unknown or any variable any name we want. I often

get bored with 'x' and 'y', so sometimes I call my variable 'Bob', or

'Sasquatch', or 'Dov' after my grandson.