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22 January, 10:19

Find the 10th term of the following geometric sequence: 2, 8, 32, 128. A. 164,357 B. 621,325 C. 524,288 D. 248,221

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  1. 22 January, 10:29
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    Common ratio = 8/2 = 32/8 = 4

    10th term = a1*r^ (n - 1) where a1 = 2, r = 4 and n = 10

    = 2 * 4^9

    = 524,288
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