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Yesterday, 11:06

If ƒ (x) = x^2 + 1, find ƒ (a + 1).

a^2 + 2

a^2+a+1

a^2+2a+2

+2
Answers (2)
  1. Yesterday, 11:15
    0
    I'm pretty sure that this is how it goes

    If ƒ (x) = x^2 + 1, find ƒ (a + 1).

    x = (a+1) so u replace x to get this:

    f (a+1) = (a+1) ^2+1

    If you square "a" it just becomes a^2 and "1" squared is just "1"

    1+1=2

    Answer: a^2+2a+2
  2. Yesterday, 11:16
    0
    The third option is the answer.
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