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Paola Bates
Mathematics
16 June, 22:52
Extraneous solution q-6 = square root 27-2q
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Jamari
16 June, 22:59
0
q = 1, q = 9
Step-by-step explanation:
Equation: q - 6 = √ (27 - 2q)
Exponents: (q - 6) ² = 27 - 2q
Simplify: q² - 12q + 36 = 27 - 2q
Subtract: q² - 10q + 9 = 0
Two numbers: a + b = - 10, ab = 9 - -> a = - 1, b = - 9
Substitute: q² - 1q - 9q + 9 = 0
Simplify: (q - 1) (q - 9) = 0
Solve: q - 1 = 0, q - 9 = 0 - -> q = 1, q = 9
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