What are the vertex, focus, and directrix of the parabola with the equation x^2+y^2-8x+4y+4=0?

vertex (4, - 3); focus (4, - 4); directrix y = - 2 vertex (-4, 3); focus (-4, - 1); directrix y = 7 vertex (4, - 3); focus (4, - 7); directrix y = 1 vertex (-4, 3); focus (-4, 2); directrix y = 4

Question

Cael Anthony

Mathematics

22 November, 17:05

What are the vertex, focus, and directrix of the parabola with the equation x^2+y^2-8x+4y+4=0?

vertex (4, - 3); focus (4, - 4); directrix y = - 2 vertex (-4, 3); focus (-4, - 1); directrix y = 7 vertex (4, - 3); focus (4, - 7); directrix y = 1 vertex (-4, 3); focus (-4, 2); directrix y = 4

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Answers (1)

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Katelyn Cameron · Answer 1

X^2+y^2-8x+4y+4=0 can be written as (x - 4) ² + (y+2) ²-16-4+4=0, or

(x - 4) ² + (y+2) ²=16, this is not a an equation of parabola, it is a circle's

its center is (4, - 2) and its radius r=4

What are the vertex, focus, and directrix of the parabola with the equation x^2+y^2-8x+4y+4=0?vertex (4, - 3); focus (4, - 4); directrix y = - 2 vertex (-4, 3); focus (-4, - 1); directrix y = 7 vertex (4, - 3); focus (4, - 7); directrix y = 1 vertex (-4, 3); focus (-4, 2); directrix y = 4

What are the vertex, focus, and directrix of the parabola with the equation x^2+y^2-8x+4y+4=0?

vertex (4, - 3); focus (4, - 4); directrix y = - 2 vertex (-4, 3); focus (-4, - 1); directrix y = 7 vertex (4, - 3); focus (4, - 7); directrix y = 1 vertex (-4, 3); focus (-4, 2); directrix y = 4