Mr. Derbyshire makes a business trip from his house to loganville in 2 hours. One hour later, he returns home in traffic at a rate 20mph less than his rate going. If Mr. Derbyshire is gone a total of 6 hours, how fast did he travel on each leg of the trip

Question

Jovan Conner

Mathematics

13 May, 14:29

Mr. Derbyshire makes a business trip from his house to loganville in 2 hours. One hour later, he returns home in traffic at a rate 20mph less than his rate going. If Mr. Derbyshire is gone a total of 6 hours, how fast did he travel on each leg of the trip

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Answers (1)

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Elsie Oneal · Answer 1

2 hours traveling+1 hour waiting=3 hours, 6hours total-3 = 3hours return trip.

X = mph on first leg

2hours*X=3hours * (X-20)

2x=3x-60

-1x=-60

x=60

60mph first leg, 40mph second leg