Nine actors audition for four different parts in a play. in how many ways can the director fill these roles?

A:368,880

B:15,120

C:3024

D:126

To solve this, we need to find the total number of combinations that can be made from 9 actors and 4 different plays. The formula for combination is:

C = n! / (n - r) ! r!

where n = 9, r = 4

C = 9! / (9 - 4) ! 4!

C = 126

Answer:

D. 126