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12 January, 00:41

a club has 10 members.

If the club is sending 3 members to a convention, how many different groups of 3 members are possible?

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Answers (2)
  1. 12 January, 00:44
    0
    That is the combination of 10 over 3, which is calculated as the quotient of factorials:

    n!/k! (n-k) !

    where n = 10 and k = 3:

    = 10!/3! (10 - 3) !

    = 10!/3!*7!

    = (10*9*8) / (3*2*1)

    = 720/6

    = 120

    therefore there a re 120 possible different groups
  2. 12 January, 01:00
    0
    Okay so you have 10 members. So you would go 10 divided by 3 that is equal to 9 with one left over.
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