The elevator of a high-rise office building provides access to all floors. if each floor is 5 meters high and the elevator travels at a rate of 7.5 meters per second, approximately how long will it take to travel from the first floor to the sixty-eighth floor?

Question

Lena Wall

Mathematics

15 April, 02:16

The elevator of a high-rise office building provides access to all floors. if each floor is 5 meters high and the elevator travels at a rate of 7.5 meters per second, approximately how long will it take to travel from the first floor to the sixty-eighth floor?

+1

Answers (1)

Know the Answer?

Kylie Nash · Answer 1

Height of each floor = 5 meters

time to travel from the first floor to 68th floor = ?

Speed of elevator = 7.5m/s

While an elevator travels from 1st floor to 68th floor, we will multiply the height of floor with 67 to get the distance covered by the elevator form 1st floor to 68th floor, the height of 68th floor will not be counted in the distance because an elevator reaches the 68th floor not covered the height of that floor.

Distance = 5 x 67 = 335m

Now calculate the time by using the formula;

time = distance / speed

= 335m / 7.5m/s

= 44.667 seconds

Thus, an elevator will take 44.667 seconds to reach 68th floor.