The perimeter of a rectangular field is 200 feet. The length of the field is 7 feet more than two times the width of the field.

Part A Write a system of two equations that could be used to find the length and width of the field. Let x represent the length of the field, and let y represent the width of the field.

Part B Solve the system of equations for x and y to determine the dimensions of the field.

Question

Poncho

Mathematics

11 August, 01:04

The perimeter of a rectangular field is 200 feet. The length of the field is 7 feet more than two times the width of the field.

Part A Write a system of two equations that could be used to find the length and width of the field. Let x represent the length of the field, and let y represent the width of the field.

Part B Solve the system of equations for x and y to determine the dimensions of the field.

+2

Answers (1)

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Kahlua · Answer 1

X = 2y + 7 ... (1)

2x + 2y = 200 ... (2)

Substituting the expression for x in equation (1) into equation (2) gives

2 (2y + 7) + 2y = 200 ... (3)

Equation (3) simplifies to

6y = 186

Therefore y = 31 feet.

Substituting the value for y into (1) gives

x = 69 feet.