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19 August, 05:27

Given a mean of 259 and a standard deviation of 229.1, what is the z-score of the value 78 rounded to the nearest tenth?

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  1. 19 August, 05:48
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    The formula for z-score is given by:

    z = (x-μ) / σ

    where;

    μ=mean

    σ=standard deviation

    thus;

    z = (78-259) / 229.1

    z=-0.790048

    z=0.8
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