How do you solve this?

3x (x+4) = 0

3x^2+12x

Step-by-step explanation:

I can't quite remember but I believe that is the answer

You distribute the 3x into the parenthesis

3x (x) + 3x (4)

3x=0 or x+4=0

x=0 or x=-4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x2+12x=0

Step 2: Factor left side of equation.

3x (x+4) = 0

Step 3: Set factors equal to 0.

3x=0 or x+4=0

x=0 or x=-4