If a programming language does not use short-circuit evaluation, what is the output of the following code fragment if the value of myInt is 0? int other = 3, myInt; if (myInt! = 0 && other % myInt! = 0) printf ("other is odd/n"); else printf ("other is even/n");

Question

Alexa Johns

Mathematics

6 May, 21:31

If a programming language does not use short-circuit evaluation, what is the output of the following code fragment if the value of myInt is 0? int other = 3, myInt; if (myInt! = 0 && other % myInt! = 0) printf ("other is odd/n"); else printf ("other is even/n");

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Answers (1)

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Colt Ortega · Answer 1

other is even.

Step-by-step explanation:

Since the value of myInt variable is assumed to be 0 and we have other = 3. In the if condition the expression is true only when the myInt is not equal to zero and and the remainder of other/myInt is not equal to zero (%modulus operator provides the remainder). myInt is 0 hence the expression returns false and the else block is executed so it prints other is even.