Solve the following system of equations. With multiplication

4x - 3y = - 11

- 7x-8y = 6

4x - 3y = - 11

-7x - 8y = 6

We need to cancel out one of the variables so let's multiply the first equation by 8 and the second by 3 and aim to cancel y.

32x - 24y = - 88

-21x - 24y = 18

Now we subtract,

53x = - 106

x = - 2

3y = 4x + 11 = 4 (-2) + 11 = 3

y = 1

Answer: (x, y) = (-2,1)

Check:

4 (-2) - 3 (1) = - 8 - 3 = - 11, good

-7 (-2) - 8 (1) = 14 - 8 = 6, good