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20 September, 16:48

Consider the sequence: 11, 21, 31, ..., ..., ... What is the 2012th term of this sequence?

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  1. 20 September, 17:00
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    let aⁿ to be the amount of term, a₁ initial term, n the terms and d distance between the numbers.

    aⁿ = a₁ + (n-1) d

    a²=11 + (2-1) (10) = 22

    a²⁰¹²=11 + (2012-1) (10) = 20121
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