For one toss of a certain coin, the probability that the outcome is heads is 0.6. If this coin is tossed 5 times, which of the following is the probability that the outcome will be heads at least 4 times?

A. (0.6) 5 (0.6) 5

B. 2 (0.6) 42 (0.6) 4

C. 3 (0.6) 43 (0.6) 4

D. 4 (0.6) 4 (0.4) + (0.6) 54 (0.6) 4 (0.4) + (0.6) 5

E. 5 (0.6) 4 (0.4) + (0.6) 5

Answer: P (x≥4) = 0.337

Step-by-step explanation: p = probability of getting head = 0.6, probability of not getting head = q = 1 - 0.6 = 0.4

n = number of times experiment was performed = 5

We are to find

P (x≥4) = 1 - P (x≤3)

We can get the value of P (x≤3) using a cumulative binomial probability table.

P (x≤3) = 0.663

P (x≥4) = 1 - 0.663

P (x≥4) = 0.337