How do i calculate (Log) 23 + (log) 93?

A property of logs, is

log ab=log a+log b so

log 23+log 93=log (23 times 93) = log 2139

assuming log to base 10 you would be solving for

10^x=2139

this is the same as

log 2139

not sure how to solve it except by puting it into a calculator or looking it up on a log table

the answer is aprox 3.3302107845715