Taylor graphs the system below on her graphing calculator and decides that f (x) = g (x) at x=0, x=1, and x=3. Provide Taylor with some feedback that explains which part of her answer is incorrect and why it is incorrect.

f (x) = 2x+1

g (x) = 2x^2+1

At x = 3. It is incorrect

f (x) ! = g (x)

Step-by-step explanation:

Lets evaluate each case

x = 0

f (0) = 2 * (0) + 1 = 0 + 1 = 1

g (0) = 2 * (0) ^2 + 1 = 0 + 1 = 1

Then f (0) = g (0) = 1

x = 1

f (1) = 2 * (1) + 1 = 2 + 1 = 3

g (1) = 2 * (1) ^2 + 1 = 2 + 1 = 3

Then f (1) = g (1) = 3

x = 3

f (3) = 2 * (3) + 1 = 6 + 1 = 7

g (3) = 2 * (3) ^2 + 1 = 18 + 1 = 19

Then f (3) ! = g (3) (They are different)