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17 January, 08:38

Factor quadratic trinomials 27x^2-90x+27

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  1. 17 January, 09:06
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    27x^2-81x-9x+27 In this case, just in your mind multiply 27 (coefficient of x^2) by the constant value 27 (the end value of the quadratic trinomial). Then find factors that give you the value - 90 when you add and 729 (27*27) when you multiply.

    Factorise the values

    27x (x-3) - 9 (x-3)

    Which will give you

    (27x-9) (x-3)
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