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11 December, 07:49

For what value of x the relation S: { (x2+3,4), (5,2) } is not a function?

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Answers (2)
  1. 11 December, 07:53
    0
    x = ±sqrt (2)

    Step-by-step explanation:

    It is not a function if the same input goes to 2 different outputs

    x^2 + 3 = 5 would cause the same input to go to 2 different outputs

    Subtract 3 from each side

    x^2 + 3-3 = 5-3

    x^2 = 2

    Take the square root of each side

    sqrt (x^2) = ±sqrt (2)

    x = ±sqrt (2)
  2. 11 December, 07:59
    0
    x = sqrt (2), - sqrt (2)

    Step-by-step explanation:

    For a function, there cannot be multiple outputs for the same input, therefore x²+3 should not be 5

    x² + 3 = 5

    x² = 2

    x = + / - sqrt (2)
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