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12 January, 07:26

A capacitor is charged to a potential difference of 12v it delivers 40% of its stored energy to a lamp what is the final potential difference across the capacitor

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  1. 12 January, 07:33
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    Call the capacitance C.

    Note the energy in a capacitor with voltage V is E = ½CV².

    Initial energy = ½C (12) ² = 72C

    40% of energy is delivered, so 60% remains. in the capacitor.

    Remaining energy = (60/100) x 72C = 43.2C

    If the final potential difference is X, the energy stored is ½CX²

    ½CX² = 43.2C

    X² = 2 x 43.2 = 86.4

    X = 9.3V
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